What is x^2+y^2=x+y+2 ?

The solution to x^2+y^2=x+y+2 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(5/2)

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x^2+y^2=x+y+2

x^{2} + y^{2} = x + y + 2

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{5}{2}

Solution steps

x^{2} + y^{2} = x + y + 2

Rewrite

x^{2} + y^{2} = x + y + 2

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, \frac{1}{2}), r = \frac{5}{2}

(x + 2)^{2} + (y - 5)^{2} = 49

x^{2} + y^{2} - 12 x - 4 y + 32 = 0

y^{2} = 2 - x^{2}

x^{2} + y^{2} - 2 x + 8 y - 127 = 0

x^{2} + y^{2} - 10 x + 6 y + 25 = 0

What is x^2+y^2=x+y+2 ?
The solution to x^2+y^2=x+y+2 is Circle with (a,b)=(1/2 , 1/2),r=sqrt(5/2)