What is (x+3)(x+3)+(y+2)(y+2)=16 ?

The solution to (x+3)(x+3)+(y+2)(y+2)=16 is Circle with (a,b)=(-3,-2),r=4

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(x+3)(x+3)+(y+2)(y+2)=16

(x + 3) (x + 3) + (y + 2) (y + 2) = 16

(a, b) = (- 3, - 2), r = 4

Solution steps

(x + 3) (x + 3) + (y + 2) (y + 2) = 16

Rewrite

(x + 3) (x + 3) + (y + 2) (y + 2) = 16

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 2), r = 4

(x + 1)^{2} + y^{2} = \frac{4}{9}

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

x^{2} + y^{2} + 10 y + 19 = 0

x^{2} + y^{2} + 4 x - 4 y - 17 = 0

x^{2} + y^{2} - 4 x + 2 y - 15 = 0

What is (x+3)(x+3)+(y+2)(y+2)=16 ?
The solution to (x+3)(x+3)+(y+2)(y+2)=16 is Circle with (a,b)=(-3,-2),r=4