What is (-x-3)^2+(-y-2)^2=2^2 ?

The solution to (-x-3)^2+(-y-2)^2=2^2 is Circle with (a,b)=(-3,-2),r=2

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(-x-3)^2+(-y-2)^2=2^2

(- x - 3)^{2} + (- y - 2)^{2} = 2^{2}

(a, b) = (- 3, - 2), r = 2

Solution steps

(- x - 3)^{2} + (- y - 2)^{2} = 2^{2}

Rewrite

(- x - 3)^{2} + (- y - 2)^{2} = 2^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 2), r = 2

y^{2} + (x - 2)^{2} = 4

x^{2} + (y + 6)^{2} = 50

(x + 3)^{2} + (y - 1)^{2} = 32

(x + 3)^{2} + (y - 1)^{2} = 34

x^{2} + y^{2} + 4 x - 6 y = 12

What is (-x-3)^2+(-y-2)^2=2^2 ?
The solution to (-x-3)^2+(-y-2)^2=2^2 is Circle with (a,b)=(-3,-2),r=2