What is 20y^2+20x^2=50 ?

The solution to 20y^2+20x^2=50 is Circle with (a,b)=(0,0),r=sqrt(5/2)

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20y^2+20x^2=50

20 y^{2} + 20 x^{2} = 50

(a, b) = (0, 0), r = \frac{5}{2}

Solution steps

20 y^{2} + 20 x^{2} = 50

Rewrite

20 y^{2} + 20 x^{2} = 50

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{5}{2}

10 x^{2} + 10 y^{2} - 80 x + 200 y + 920 = 0

4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0

x^{2} + y^{2} - 2 x + 4 y - 21 = 0

(x - 1)^{2} + (y - 9)^{2} = 15

(x - 3)^{2} + (y - 4)^{2} = 7

What is 20y^2+20x^2=50 ?
The solution to 20y^2+20x^2=50 is Circle with (a,b)=(0,0),r=sqrt(5/2)