What is y^2+(x+3)^2=7 ?

The solution to y^2+(x+3)^2=7 is Circle with (a,b)=(-3,0),r=sqrt(7)

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y^2+(x+3)^2=7

y^{2} + (x + 3)^{2} = 7

(a, b) = (- 3, 0), r = 7

Solution steps

y^{2} + (x + 3)^{2} = 7

Rewrite

y^{2} + (x + 3)^{2} = 7

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 7

x^{2} + y^{2} = 23

x^{2} + y^{2} = 27

(x - 1)^{2} + (y - 2)^{2} = 64

(x^{2} - 12 x + 36) + (y^{2} - 14 y + 49) - 64 = 0

x^{2} + y^{2} = 37

What is y^2+(x+3)^2=7 ?
The solution to y^2+(x+3)^2=7 is Circle with (a,b)=(-3,0),r=sqrt(7)