What is x^2+y^2-6x+10y+25=0 ?

The solution to x^2+y^2-6x+10y+25=0 is Circle with (a,b)=(3,-5),r=3

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x^2+y^2-6x+10y+25=0

x^{2} + y^{2} - 6 x + 10 y + 25 = 0

(a, b) = (3, - 5), r = 3

Solution steps

x^{2} + y^{2} - 6 x + 10 y + 25 = 0

Rewrite

x^{2} + y^{2} - 6 x + 10 y + 25 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, - 5), r = 3

(x - 1)^{2} + (y - 7)^{2} = 25

(x - 15)^{2} + ((y - (- 20)))^{2} = 9^{2}

(x - 12)^{2} + (y - 2)^{2} = 64

x^{2} + y^{2} - 14 x + 2 y + 10 = 0

3 x^{2} + 30 x + 3 y^{2} - 12 y + 12 = 0

What is x^2+y^2-6x+10y+25=0 ?
The solution to x^2+y^2-6x+10y+25=0 is Circle with (a,b)=(3,-5),r=3