What is x^2+4x+y^2-18y=18 ?

The solution to x^2+4x+y^2-18y=18 is Circle with (a,b)=(-2,9),r=sqrt(103)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+4x+y^2-18y=18

x^{2} + 4 x + y^{2} - 18 y = 18

(a, b) = (- 2, 9), r = 103

Solution steps

x^{2} + 4 x + y^{2} - 18 y = 18

Rewrite

x^{2} + 4 x + y^{2} - 18 y = 18

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 9)^{2} = (103)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 9), r = 103

x^{2} + y^{2} - 9 x + 4 y - 123 = 0

x^{2} - 2 y + y^{2} - 24 = 0

5 - x^{2} - 2 x - y^{2} = 0

2 x^{2} + 2 y^{2} - 8 x + 12 y - 8 = 0

(x + 1)^{2} + (y + 6)^{2} = 100

What is x^2+4x+y^2-18y=18 ?
The solution to x^2+4x+y^2-18y=18 is Circle with (a,b)=(-2,9),r=sqrt(103)