What is x^2+y^2-5x+47=46 ?

The solution to x^2+y^2-5x+47=46 is Circle with (a,b)=(5/2 ,0),r=(sqrt(21))/2

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x^2+y^2-5x+47=46

x^{2} + y^{2} - 5 x + 47 = 46

(a, b) = (\frac{5}{2}, 0), r = \frac{21}{2}

Solution steps

x^{2} + y^{2} - 5 x + 47 = 46

Rewrite

x^{2} + y^{2} - 5 x + 47 = 46

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - 0)^{2} = (\frac{21}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, 0), r = \frac{21}{2}

(x + 3)^{2} + (y - 2)^{2} = 13

2 x^{2} + 2 y^{2} + 10 x + 12 y = - 12

x^{2} + y^{2} - 6 x + 4 y + 3 = 0

(x - 3)^{2} + (y - 2)^{2} = 49

(x + 4)^{2} + (y - 6)^{2} = 48

What is x^2+y^2-5x+47=46 ?
The solution to x^2+y^2-5x+47=46 is Circle with (a,b)=(5/2 ,0),r=(sqrt(21))/2