What is ((x-1)^2)/(16)+((y+2)^2)/(16)=1 ?

The solution to ((x-1)^2)/(16)+((y+2)^2)/(16)=1 is Circle with (a,b)=(1,-2),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/(16)+((y+2)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 1

(a, b) = (1, - 2), r = 4

Solution steps

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 1

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 4

(x - 4)^{2} + (y + 1)^{2} = 8

x^{2} + y^{2} - 8 x - 4 y - 5 = 0

4 x^{2} + 4 y^{2} - 12 x + 16 y - 10 = 0

(x + 2)^{2} + (y - 1)^{2} = 16

(x + 4)^{2} + (y + 4)^{2} = 16

What is ((x-1)^2)/(16)+((y+2)^2)/(16)=1 ?
The solution to ((x-1)^2)/(16)+((y+2)^2)/(16)=1 is Circle with (a,b)=(1,-2),r=4