What is x^2-5x+y^2+4y=46 ?

The solution to x^2-5x+y^2+4y=46 is Circle with (a,b)=(5/2 ,-2),r= 15/2

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x^2-5x+y^2+4y=46

x^{2} - 5 x + y^{2} + 4 y = 46

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

Solution steps

x^{2} - 5 x + y^{2} + 4 y = 46

Rewrite

x^{2} - 5 x + y^{2} + 4 y = 46

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - (- 2))^{2} = (\frac{15}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, - 2), r = \frac{15}{2}

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

x^{2} + y^{2} + x - y = 0

3 (x + 1)^{2} + 3 (y - 2)^{2} = 12

x^{2} + y^{2} + 6 x + 12 y + 9 = 0

x^{2} + y^{2} - 16 x + 15 = 0

What is x^2-5x+y^2+4y=46 ?
The solution to x^2-5x+y^2+4y=46 is Circle with (a,b)=(5/2 ,-2),r= 15/2