What is 3(x-2)^2+3y^2=3 ?

The solution to 3(x-2)^2+3y^2=3 is Circle with (a,b)=(2,0),r=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3(x-2)^2+3y^2=3

3 (x - 2)^{2} + 3 y^{2} = 3

(a, b) = (2, 0), r = 1

Solution steps

3 (x - 2)^{2} + 3 y^{2} = 3

Rewrite

3 (x - 2)^{2} + 3 y^{2} = 3

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 1

a^{2} + b^{2} = 3

x^{2} - 16 x + y^{2} + 8 y + 80 = 81

x^{2} + y^{2} - 10 x - 10 y = - 25

4 x^{2} + 40 x + 4 y^{2} - 32 y = 5

x^{2} + y^{2} - 6 x - 2 y + 1 = 0

What is 3(x-2)^2+3y^2=3 ?
The solution to 3(x-2)^2+3y^2=3 is Circle with (a,b)=(2,0),r=1