What is (x^2)/4+(y^2)/4 =1 ?

The solution to (x^2)/4+(y^2)/4 =1 is Circle with (a,b)=(0,0),r=2

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(x^2)/4+(y^2)/4 =1

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 1

(a, b) = (0, 0), r = 2

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

16 + x^{2} + y^{2} - 8 x - 6 y = 0

x^{2} + x + y^{2} + 2 y = 0

(x + 1)^{2} + (y - 3)^{2} = 4

x^{2} + y^{2} - 2 x + 2 y - 7 = 0

x^{2} - 8 x + y^{2} - 6 y + 21 = 0

What is (x^2)/4+(y^2)/4 =1 ?
The solution to (x^2)/4+(y^2)/4 =1 is Circle with (a,b)=(0,0),r=2