What is the area (p^2)/(16) ?

The area (p^2)/(16) is Unbounded

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area (p^2)/(16)

area

\frac{p ^{2}}{16}

Unbounded

Solution steps

y = \frac{p ^{2}}{16}

Rewrite

y = \frac{p ^{2}}{16}

in the standard form:

4 \cdot 4 (y - 0) = (p - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 4

Parabola's area is always unbounded

Unbounded

x = y^{2} + 1

0.9 x^{2} + 6.4 x + 7.7

x = y^{2} + 2

169 c m^{2}

[(x^{2} + 10) - (7 x^{2})]