What is the inverse of y=(3x-4)^2 ?

The inverse of y=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3

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inverse of y=(3x-4)^2

inverse

y = (3 x - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

Solution steps

y = (3 x - 4)^{2}

Replace

x

with

y

x = (3 y - 4)^{2}

Solve for

y, x = (3 y - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

g (x) = x - 9

x^{2} - 3 x + 2

\frac{1}{2} x + \frac{2}{3} y = - 2

f (x) = x + 6 \cdot x - 1

f (x) = \frac{317 + x}{5}

What is the inverse of y=(3x-4)^2 ?
The inverse of y=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3