What is the derivative of-x^4+sqrt(x) ?

The derivative of-x^4+sqrt(x) is -4x^3+1/(2sqrt(x))

What is the first derivative of-x^4+sqrt(x) ?

The first derivative of-x^4+sqrt(x) is -4x^3+1/(2sqrt(x))

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\frac{d}{d x} (- x^{4} + x)

- 4 x^{3} + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (- x^{4} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{4}) + \frac{d}{d x} (x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (x) = \frac{1}{2 x}

= - 4 x^{3} + \frac{1}{2 x}

\frac{x d y}{d x} - (1 + x) y = x y^{2}

\int (3 - \frac{1}{x})^{- 2} (\frac{1}{x ^{2}}) d x

\int \frac{x ^{3}}{( 5 - x ^{4} ) ^{5}} d x

y = 4 (x - \frac{1}{x})^{3}, at x = 2

\int \frac{1}{( x - 1 ) 4 x ^{2} - 8 x + 3} d x

What is the derivative of-x^4+sqrt(x) ?
The derivative of-x^4+sqrt(x) is -4x^3+1/(2sqrt(x))
What is the first derivative of-x^4+sqrt(x) ?
The first derivative of-x^4+sqrt(x) is -4x^3+1/(2sqrt(x))