What is the derivative of (x^2/(x+1)) ?

The derivative of (x^2/(x+1)) is (x^2+2x)/((x+1)^2)

What is the first derivative of (x^2/(x+1)) ?

The first derivative of (x^2/(x+1)) is (x^2+2x)/((x+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{2}}{x + 1})

\frac{x ^{2} + 2 x}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x ^{2}}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x + 1) = 1

= \frac{2 x ( x + 1 ) - 1 \cdot x ^{2}}{( x + 1 ) ^{2}}

Simplify

\frac{2 x ( x + 1 ) - 1 \cdot x ^{2}}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x}{( x + 1 ) ^{2}}

y^{^{'}} + \frac{y}{t} = 2 cos (3 t)

\frac{d}{d x} (x^{2} (x - 1)^{3})

x \to 0 lim (\frac{( 2. 8 ^{x} - 1 )}{x})

\int_{0}^{\frac{1}{2}} 1 - 4 x^{2} d x

\int \frac{6}{x x ^{2} + 1} d x

What is the derivative of (x^2/(x+1)) ?
The derivative of (x^2/(x+1)) is (x^2+2x)/((x+1)^2)
What is the first derivative of (x^2/(x+1)) ?
The first derivative of (x^2/(x+1)) is (x^2+2x)/((x+1)^2)