What is the tangent of y=2e^xcos(x),(0,2) ?

The tangent of y=2e^xcos(x),(0,2) is y=2x+2

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tangent of y=2e^xcos(x),(0,2)

tangent of

y = 2 e^{x} cos (x), (0, 2)

y = 2 x + 2

Solution steps

Find the slope of

y = 2 e^{x} cos (x) : \frac{d y}{d x} = 2 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 2 e^{x} cos (x)

(0, 2) : m = 2

Find the line with slope m=

2

and passing through

(0, 2) : y = 2 x + 2

y = 2 x + 2

\frac{d}{d x} (cos^{3} (4 x^{2}))

\frac{d}{d x} (ln (a x^{n}))

x \to \infty lim (5^{- x})

\frac{2 t}{4 + t ^{2}}

x \to 0 lim (\frac{5 x ^{3}}{x ^{3}})

What is the tangent of y=2e^xcos(x),(0,2) ?
The tangent of y=2e^xcos(x),(0,2) is y=2x+2