Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}-2y^'+y=2e^t,y(0)=1,y^'(0)=1x^{''}-x^'-6x=5ty^{''}-2y^'-3y=8e^{-t}y^{''}-y^'+4y=x^3e^{2x}+xe^{2x}y^{''}-2y^'=2+e^{2x}
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-3y^'-4y=t^2 ?
The solution for y^{''}-3y^'-4y=t^2 is y=c_{1}e^{4t}+c_{2}e^{-t}-(t^2)/4+(3t)/8-13/32