What is the solution for (dt)/(dy)=e^{6t+3y},y(0)=16 ?

The solution for (dt)/(dy)=e^{6t+3y},y(0)=16 is y=(ln(-1/2 e^{-6t}+e^{48}+1/2))/3

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(dt)/(dy)=e^{6t+3y},y(0)=16

\frac{d t}{d y} = e^{6 t + 3 y}, y (0) = 16

y = \frac{ln ( - \frac{1}{2} e ^{- 6 t} + e ^{48} + \frac{1}{2} )}{3}

Solution steps

\frac{d}{d y} (t) = e^{6 t + 3 y}

Solve separable ODE:

y = \frac{ln ( - \frac{1}{2} e ^{- 6 t} + e ^{48} + \frac{1}{2} )}{3}

y = \frac{ln ( - \frac{1}{2} e ^{- 6 t} + e ^{48} + \frac{1}{2} )}{3}

What is the solution for (dt)/(dy)=e^{6t+3y},y(0)=16 ?
The solution for (dt)/(dy)=e^{6t+3y},y(0)=16 is y=(ln(-1/2 e^{-6t}+e^{48}+1/2))/3