Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
(x^2+1)y^'+y^2=0x^2dy-y^2dx=0y^'=((3t^2+4t+2))/((2y-2))ytan(x)(dy)/(dx)=(4+y^2)sec(x^2)(dy)/(dx)=c*y
Frequently Asked Questions (FAQ)
What is the solution for y^'+4y+16=0,y(0)=2 ?
The solution for y^'+4y+16=0,y(0)=2 is y=6e^{-4t}-4