Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
2xydx=(5-x^2)dyy^'=y^2+1,y(1)=0dy=θ^3dθ(dy)/(dx)y=((5x^2+2)(3x+9))/(8x-9)3e^{2x}(dy)/(dx)=-4*x/(y^2)
Frequently Asked Questions (FAQ)
What is the solution for 2y^'+2y=10,y(0)=0 ?
The solution for 2y^'+2y=10,y(0)=0 is y=-5e^{-t}+5