What is the solution for y^'=((1+x^2))/y ?

The solution for y^'=((1+x^2))/y is y=sqrt(2x+(2x^3)/3+c_{1)},y=-sqrt(2x+(2x^3)/3+c_{1)}

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y^'=((1+x^2))/y

y^{^{'}} = \frac{( 1 + x ^{2} )}{y}

y = 2 x + \frac{2 x ^{3}}{3} + c_{1}, y = - 2 x + \frac{2 x ^{3}}{3} + c_{1}

Solution steps

y^{'} (x) = \frac{( 1 + x ^{2} )}{y}

Solve separable ODE:

y = 2 x + \frac{2 x ^{3}}{3} + c_{1}, y = - 2 x + \frac{2 x ^{3}}{3} + c_{1}

y = 2 x + \frac{2 x ^{3}}{3} + c_{1}, y = - 2 x + \frac{2 x ^{3}}{3} + c_{1}

What is the solution for y^'=((1+x^2))/y ?
The solution for y^'=((1+x^2))/y is y=sqrt(2x+(2x^3)/3+c_{1)},y=-sqrt(2x+(2x^3)/3+c_{1)}