What is the solution for d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ)) ?

The solution for d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ)) is y(θ)=e^{integral of (θ-3)/(θcos(θ))}

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d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ))

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

y (θ) = e^{\int \frac{θ - 3}{θ c o s ( θ )} d θ}

Solution steps

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

ln (y (θ)) = \int \frac{θ - 3}{θ cos ( θ )} d θ

ln (y (θ)) = \int \frac{θ - 3}{θ cos ( θ )} d θ

Isolate

y (θ) : y (θ) = e^{\int \frac{θ - 3}{θ c o s ( θ )} d θ}

y (θ) = e^{\int \frac{θ - 3}{θ c o s ( θ )} d θ}

What is the solution for d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ)) ?
The solution for d/(dθ)(ln(y(θ)))=(θ-3)/(θcos(θ)) is y(θ)=e^{integral of (θ-3)/(θcos(θ))}