What is the solution for y^'=((x+xy^2)/(4y)) ?

The solution for y^'=((x+xy^2)/(4y)) is y=sqrt(e^{(x^2)/4+c_{1)}-1},y=-sqrt(e^{(x^2)/4+c_{1)}-1}

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y^'=((x+xy^2)/(4y))

y^{^{'}} = (\frac{x + x y ^{2}}{4 y})

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

Solution steps

y^{'} (x) = (\frac{x + x y ^{2}}{4 y})

Solve separable ODE:

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

What is the solution for y^'=((x+xy^2)/(4y)) ?
The solution for y^'=((x+xy^2)/(4y)) is y=sqrt(e^{(x^2)/4+c_{1)}-1},y=-sqrt(e^{(x^2)/4+c_{1)}-1}