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Popular Calculus >

(xy)(dy)/(dx)=1+y^2

Solution

(x y) \frac{d y}{d x} = 1 + y^{2}

Solution

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

Solution steps

(x y) \frac{d y}{d x} = 1 + y^{2}

Solve separable ODE:

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

y = c_{1} x^{2} - 1, y = - c_{1} x^{2} - 1

Graph

Popular Examples

y^'=e^{t+y},y(ln(2))=1

(dy)/(dx)x^2y-y^2=8

(yln(x-2))ydx=xdy

y^'=6y^{-4},y(0)=5

(dy)/(dx)=((2x^2))/(y^2)

Frequently Asked Questions (FAQ)

What is the solution for (xy)(dy)/(dx)=1+y^2 ?
The solution for (xy)(dy)/(dx)=1+y^2 is y=sqrt(c_{1)x^2-1},y=-sqrt(c_{1)x^2-1}