What is the solution for y^'= 4/(ye^{x+4y)} ?

The solution for y^'= 4/(ye^{x+4y)} is y=(\W((-64e^{-x}+c_{1})/e))/(4)+1/4

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y^'= 4/(ye^{x+4y)}

y^{^{'}} = \frac{4}{y e ^{x + 4 y}}

y = \frac{W ( \frac{- 64 e ^{- x} + c _{1}}{e} )}{4} + \frac{1}{4}

Solution steps

y^{'} (x) = \frac{4}{y e ^{x + 4 y}}

Solve separable ODE:

y = \frac{W ( \frac{- 64 e ^{- x} + c _{1}}{e} )}{4} + \frac{1}{4}

y = \frac{W ( \frac{- 64 e ^{- x} + c _{1}}{e} )}{4} + \frac{1}{4}

What is the solution for y^'= 4/(ye^{x+4y)} ?
The solution for y^'= 4/(ye^{x+4y)} is y=(\W((-64e^{-x}+c_{1})/e))/(4)+1/4