What is the solution for yx+12x+(ln(x)-3)y^'=0 ?

The solution for yx+12x+(ln(x)-3)y^'=0 is y=e^{integral of-x/(ln(x)-3)}-12

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yx+12x+(ln(x)-3)y^'=0

y x + 12 x + (ln (x) - 3) y^{^{'}} = 0

y = e^{\int - \frac{x}{l n ( x ) - 3} d x} - 12

Solution steps

y x + 12 x + (ln (x) - 3) y^{'} (x) = 0

Solve separable ODE:

y = e^{\int - \frac{x}{l n ( x ) - 3} d x} - 12

y = e^{\int - \frac{x}{l n ( x ) - 3} d x} - 12

What is the solution for yx+12x+(ln(x)-3)y^'=0 ?
The solution for yx+12x+(ln(x)-3)y^'=0 is y=e^{integral of-x/(ln(x)-3)}-12