What is the solution for +2ydy-ln(t)dt=e^tdt ?

The solution for +2ydy-ln(t)dt=e^tdt is y=sqrt(e^t+tln(t)-t+c_{1)},y=-sqrt(e^t+tln(t)-t+c_{1)}

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+2ydy-ln(t)dt=e^tdt

+ 2 y d y - ln (t) d t = e^{t} d t

y = e^{t} + t ln (t) - t + c_{1}, y = - e^{t} + t ln (t) - t + c_{1}

Solution steps

+ 2 y d y - ln (t) d t = e^{t} d t

Solve separable ODE:

y = e^{t} + t ln (t) - t + c_{1}, y = - e^{t} + t ln (t) - t + c_{1}

y = e^{t} + t ln (t) - t + c_{1}, y = - e^{t} + t ln (t) - t + c_{1}

What is the solution for +2ydy-ln(t)dt=e^tdt ?
The solution for +2ydy-ln(t)dt=e^tdt is y=sqrt(e^t+tln(t)-t+c_{1)},y=-sqrt(e^t+tln(t)-t+c_{1)}