What is the solution for y^'=e^{7x-10y},y(0)=0 ?

The solution for y^'=e^{7x-10y},y(0)=0 is y=(ln(10/7 e^{7x}-3/7))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'=e^{7x-10y},y(0)=0

y^{^{'}} = e^{7 x - 10 y}, y (0) = 0

y = \frac{ln ( \frac{10}{7} e ^{7 x} - \frac{3}{7} )}{10}

Solution steps

y^{'} (x) = e^{7 x - 10 y}

Solve separable ODE:

y = \frac{ln ( \frac{10}{7} e ^{7 x} - \frac{3}{7} )}{10}

y = \frac{ln ( \frac{10}{7} e ^{7 x} - \frac{3}{7} )}{10}

What is the solution for y^'=e^{7x-10y},y(0)=0 ?
The solution for y^'=e^{7x-10y},y(0)=0 is y=(ln(10/7 e^{7x}-3/7))/(10)