What is the solution for y^'=((3t^2))/(4+2y) ?

The solution for y^'=((3t^2))/(4+2y) is y=-2+sqrt(t^3+c_{1)+4},y=-sqrt(t^3+c_{1)+4}-2

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y^'=((3t^2))/(4+2y)

y^{^{'}} = \frac{( 3 t ^{2} )}{4 + 2 y}

y = - 2 + t^{3} + c_{1} + 4, y = - t^{3} + c_{1} + 4 - 2

Solution steps

y^{'} (t) = \frac{( 3 t ^{2} )}{4 + 2 y}

Solve separable ODE:

y = - 2 + t^{3} + c_{1} + 4, y = - t^{3} + c_{1} + 4 - 2

y = - 2 + t^{3} + c_{1} + 4, y = - t^{3} + c_{1} + 4 - 2

What is the solution for y^'=((3t^2))/(4+2y) ?
The solution for y^'=((3t^2))/(4+2y) is y=-2+sqrt(t^3+c_{1)+4},y=-sqrt(t^3+c_{1)+4}-2