Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
(1+x^2)dy+2xydx=03y^'=yy^'= y/(sqrt(1-x^2))(dy)/(dx)=7\sqrt[4]{xy}(dy)/(dt)+sqrt([1+t^2])*e^{-t}y=0,y[0]=1
Frequently Asked Questions (FAQ)
What is the solution for y^'=1+y^2,y(0)=1 ?
The solution for y^'=1+y^2,y(0)=1 is y=tan(t+pi/4)