Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
ty^'+2y= 1/2y^'=(1-5x)y^2,y(0)=-1/8(dy)/(dx)=e^{2x+y},y(0)=0(dy)/(dx)=y+5,y(3)=2(dp)/(dt)=0.25p(1-p*10^{-4})
Frequently Asked Questions (FAQ)
What is the solution for y*y^'-x=0 ?
The solution for y*y^'-x=0 is y=sqrt(x^2+c_{1)},y=-sqrt(x^2+c_{1)}