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Popular Calculus >

y^'=4x^2y+5xy

Solution

y^{^{'}} = 4 x^{2} y + 5 x y

Solution

y = e^{\frac{4 x ^{3}}{3} + \frac{5 x ^{2}}{2} + c_{1}}

Solution steps

y^{'} (x) = 4 x^{2} y + 5 x y

Solve separable ODE:

y = e^{\frac{4 x ^{3}}{3} + \frac{5 x ^{2}}{2} + c_{1}}

y = e^{\frac{4 x ^{3}}{3} + \frac{5 x ^{2}}{2} + c_{1}}

Graph

Popular Examples

(dy)/(dx)=2x-2xy

e^{2y}y^'=x^2-6x,y(1)=ln(3)

x^2(dy)/(dx)+y=1

(dy)/(dx)=e^{3x-3y}

(dy}{dx}=\frac{((x^2)(y^2)))/5

Frequently Asked Questions (FAQ)

What is the solution for y^'=4x^2y+5xy ?
The solution for y^'=4x^2y+5xy is y=e^{(4x^3)/3+(5x^2)/2+c_{1}}