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Popular Calculus >

y^'=1+2y

Solution

y^{^{'}} = 1 + 2 y

Solution

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

Solution steps

y^{'} (t) = 1 + 2 y

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=1+2y ?
The solution for y^'=1+2y is y=(e^{2t+c_{1}})/2-1/2