What is the solution for y^'=x^2+y^2+x^2y^2+1 ?

The solution for y^'=x^2+y^2+x^2y^2+1 is y=tan((x^3)/3+x+c_{1})

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y^'=x^2+y^2+x^2y^2+1

y^{^{'}} = x^{2} + y^{2} + x^{2} y^{2} + 1

y = tan (\frac{x ^{3}}{3} + x + c_{1})

Solution steps

y^{'} (x) = x^{2} + y^{2} + x^{2} y^{2} + 1

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + x + c_{1})

y = tan (\frac{x ^{3}}{3} + x + c_{1})

What is the solution for y^'=x^2+y^2+x^2y^2+1 ?
The solution for y^'=x^2+y^2+x^2y^2+1 is y=tan((x^3)/3+x+c_{1})