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Popular Calculus >

u^'=3e^{8x-\H(x)}

Solution

u^{^{'}} = 3 e^{8 x - H (x)}

Solution

u (x) = \int 3 e^{8 x - H (x)} d x

Solution steps

u^{'} (x) = 3 e^{8 x - H (x)}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

u (x) = \int 3 e^{8 x - H (x)} d x

u (x) = \int 3 e^{8 x - H (x)} d x

Popular Examples

y^'=((3x^2+4x-4))/(2y-4),y(1)=3

xydy=(1+y^2)dx,y(2)=3

y^5(dy)/(dx)=3x^3y^6-9x^3

y^'= 1/(3y^2(x^2+1))

Frequently Asked Questions (FAQ)

What is the solution for u^'=3e^{8x-\H(x)} ?
The solution for u^'=3e^{8x-\H(x)} is u(x)=integral of 3e^{8x-\H(x)}