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Beliebt Rechnen >

x^'=x(t^2-1)(t^2-9),x(0)=1

Lösung

x^{^{'}} = x (t^{2} - 1) (t^{2} - 9), x (0) = 1

Lösung

x = e^{\frac{t ^{5}}{5} - \frac{10 t ^{3}}{3} + 9 t}

Schritte zur Lösung

x^{'} (t) = x (t^{2} - 1) (t^{2} - 9)

Solve separable ODE:

x = e^{\frac{t ^{5}}{5} - \frac{10 t ^{3}}{3} + 9 t}

x = e^{\frac{t ^{5}}{5} - \frac{10 t ^{3}}{3} + 9 t}

Graph

Beliebte Beispiele

y^'=(t(4y-y^2))/3

y^{^{'}} = \frac{t ( 4 y - y ^{2} )}{3}

(dy)/(dx)y=ln(2-x-x^2)

\frac{d y}{d x} y = ln (2 - x - x^{2})

(dP)/(dt)=P(7-P)-49/4

\frac{d P}{d t} = P (7 - P) - \frac{49}{4}

y^{^{'}} + \frac{3}{x} y = 0

y(1+x^2)y^'-x(1+y^2)=0,y(0)=1

y (1 + x^{2}) y^{^{'}} - x (1 + y^{2}) = 0, y (0) = 1