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Popular Calculus >

y^'= x/(ye^{y+x^2)}

Solution

y^{^{'}} = \frac{x}{y e ^{y + x^{2}}}

Solution

y = W (\frac{- e ^{- x^{2}} + c _{1}}{2 e}) + 1

Solution steps

y^{'} (x) = \frac{x}{y e ^{y + x^{2}}}

Solve separable ODE:

y = W (\frac{- e ^{- x^{2}} + c _{1}}{2 e}) + 1

y = W (\frac{- e ^{- x^{2}} + c _{1}}{2 e}) + 1

Popular Examples

(xy)^2y^'=(x+5)/(sqrt(y))

(dy)/(dx)=y(2x^2+1)

(dy)/(dx)=((x^2-1)/(y^2))

(dy)/(dx)=y(2x^2+4)

Frequently Asked Questions (FAQ)

What is the solution for y^'= x/(ye^{y+x^2)} ?
The solution for y^'= x/(ye^{y+x^2)} is y=\W((-e^{-x^2}+c_{1})/(2e))+1