Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
y^'+2e^{x+y}=0(dy)/(dx)=\sqrt[3]{y}dx+cos(t)xdt-cos(t)dt=0,x(0)=-1(3x^2+2)^3(dy)/(dx)-xy^2=0(dy)/(dt)=(yt)^{1/5}
Frequently Asked Questions (FAQ)
What is the solution for y^'=6y ?
The solution for y^'=6y is y=e^{6t+c_{1}}