Solution
Solution
Solution steps
Solve separable ODE:
Graph
Popular Examples
x^2y^'+1/(y^2)=0,y(1)=2(dv)/(dt)=2-0.1v,v(0)=0(dy)/(dx)+1/x y= 1/(xy^2)(x^2+1)yy^'=1dy(xy-2x+4y-8)-dx(xy+3x-y-3)=0
Frequently Asked Questions (FAQ)
What is the solution for xy^'+6y=0 ?
The solution for xy^'+6y=0 is y=(c_{1})/(x^6)