Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=1 to infinity of n-2sum from n=3 to infinity of 6/((n^2-1))sum from n=1 to infinity of n(1+n^2)^1sum from n=1 to infinity of n/((n+4)^4)sum from n=1 to infinity of 8/(n^7+9)

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 4/(5n) ?

    The sum from n=0 to infinity of 4/(5n) is diverges