Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=1 to infinity of n!(-e)^{-6n}sum from n=0 to infinity}2^{2-n of*3^nsum from n=0 to infinity of (n+1)(1)^nsum from n=1 to infinity of 3/((4n+5)^3)sum from r=1 to infinity of r(2r-1)

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 7/n ?

    The sum from n=0 to infinity of 7/n is diverges