Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=0 to infinity of n^3e^{-n^2}sum from k=1 to infinity of (1/2)^{k-1}sum from n=0 to infinity of 4/(5^{n/3)}sum from n=0 to infinity of 1/esum from n=2 to infinity of 3^{-n}

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 5/(2n) ?

    The sum from n=0 to infinity of 5/(2n) is diverges