Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Ratio Test:converges

Popular Examples

sum from n=0 to infinity of 3/(n^2+n-2)sum from n=1 to infinity of (5/8)^{n-1}sum from k=2 to infinity of (-0.4)^ksum from n=0 to infinity of 7e^{-7n}sum from n=1 to infinity of-1/(6^n)

Frequently Asked Questions (FAQ)

  • What is the sum from k=3 to infinity of 5(1/3)^k ?

    The sum from k=3 to infinity of 5(1/3)^k is converges