Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges

Popular Examples

sum from n=1 to infinity of n(5/6)^nsum from n=1 to infinity of 5/(n^9)sum from n=3 to infinity of (1/2)^nsum from n=1 to infinity of 1/((6n)^6)sum from n=1 to infinity of 2/(e^n)

Frequently Asked Questions (FAQ)

  • What is the sum from n=0 to infinity of 6/n ?

    The sum from n=0 to infinity of 6/n is diverges