Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply p-Series Test:converges

Popular Examples

sum from n=2 to infinity of (-0.7)^nsum from n=1 to infinity of (1-n)/(n2^n)sum from n=1 to infinity of 1/(6+e^{-n)}sum from n=2 to infinity of 2/(nln(n))sum from n=1 to infinity of 5^{-3n}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 1/(4n^2) ?

    The sum from n=1 to infinity of 1/(4n^2) is converges