What are the solutions to the equation x^2-6x+5=0 ?

The solutions to the equation x^2-6x+5=0 are x=5,x=1

Find the zeros of x^2-6x+5=0

The zeros of x^2-6x+5=0 are x=5,x=1

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x^{2} - 6 x + 5 = 0

x = 5, x = 1

Solution steps

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

\frac{8}{18}

50 = 126 t - 16 t^{2}

10 - 3 x^{2} > x^{2} + 10 - x

C = \frac{5}{9} (50 - 32)

(4 x)^{2}

What are the solutions to the equation x^2-6x+5=0 ?
The solutions to the equation x^2-6x+5=0 are x=5,x=1
Find the zeros of x^2-6x+5=0
The zeros of x^2-6x+5=0 are x=5,x=1